at a point on level ground, the angle of elevation of a vertical tower is found to be such that it’s tangent is5/12.on walking 192 meters towards the tower, the tangent of the angel of elevation is3/4. find the height of the tower
2 thoughts on “at a point on level ground, the angle of elevation of a vertical tower is found to be such that it’s tangent is5/12.on walking 192”
Solution. Let AB be the vertical tower and C and D be two point such that CD= 192m. let ∠ ACB =θ and ∠ ADB = ∝. Hence, the height of the tower is 180 m.
Solution. Let AB be the vertical tower and C and D be two point such that CD= 192m. let ∠ ACB =θ and ∠ ADB = ∝. Hence, the height of the tower is 180 m.
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