Zahid had invested in a bank scheme which of interested 8.6 % annual for 7.8 year how much interest will be invested for 20000 rupees About the author Amaya
Given:– •Rate of interest=8.6% •Time is given=7.8years •Principal = 20000rupees To Find:– •How much interest will be invested Solution:– we have, Principal=20000rupees Rate=8.6% Time=7.8years Using Formula: [tex] \: \: \sf \: simple \: interest = \frac{principal \times rate \times time}{100} [/tex] Now substitue the values, [tex] \: \: \sf \: s.i = \frac{20000 \times 86 \times 78}{100 \times 10 \times 10} \\ \\ \: \: \sf \: s.i = 2 \times 86 \times 78 \\ \\ \: \: \sf \: s.i = 13416 \: rupees[/tex] Henceforth,Simple Interest is 13416 rupees. _____________________________ Extra Info… •Principal=Simple Interest *100/Rate*time •Time=Simple Interest*100/Principal*rate •Rate=Simple Interest*100/Principal*time •Amount=Principal+Simple Interest •Principal=Amount-Simple Interest •Simple Interest=Amount-Principal Reply
Given:–
•Rate of interest=8.6%
•Time is given=7.8years
•Principal = 20000rupees
To Find:–
•How much interest will be invested
Solution:–
we have,
Using Formula:
[tex] \: \: \sf \: simple \: interest = \frac{principal \times rate \times time}{100} [/tex]
Now substitue the values,
[tex] \: \: \sf \: s.i = \frac{20000 \times 86 \times 78}{100 \times 10 \times 10} \\ \\ \: \: \sf \: s.i = 2 \times 86 \times 78 \\ \\ \: \: \sf \: s.i = 13416 \: rupees[/tex]
Henceforth,Simple Interest is 13416 rupees.
_____________________________
Extra Info…
•Principal=Simple Interest *100/Rate*time
•Time=Simple Interest*100/Principal*rate
•Rate=Simple Interest*100/Principal*time
•Amount=Principal+Simple Interest
•Principal=Amount-Simple Interest
•Simple Interest=Amount-Principal