Find the square of: (i) (root 7+3) (ii) (root 5- root 3) (iii) (4+2 root 3) (iv) (6-3 root 2) (v) (11-3 root 3) About the author Alaia
Answer: 1) √7 + 3 = (√7 + 3)² = 7 + 9 + 2(√7)(3) = 16 + 6√7 2) √5 – √3 = (√5 – √3)² = 5 + 3 – 2(√5)(√3) = 8 – 2√15 3) 4 + 2√3 = (4 + 2√3)² = 16 + 12 + 2(4)(2√3) = 28 + 16√3 4) 6 – 3√2 = (6 – 3√2)² = 36 + 18 – 2(6)(3√2) = 54 – 36√2 5) 11 – 3√3 = (11 – 3√3)² = 121 + 27 – 2(11)(3√3) = 148 – 66√3 mark this as brainliast. Reply
Answer:
1) √7 + 3 = (√7 + 3)²
= 7 + 9 + 2(√7)(3)
= 16 + 6√7
2) √5 – √3 = (√5 – √3)²
= 5 + 3 – 2(√5)(√3)
= 8 – 2√15
3) 4 + 2√3 = (4 + 2√3)²
= 16 + 12 + 2(4)(2√3)
= 28 + 16√3
4) 6 – 3√2 = (6 – 3√2)²
= 36 + 18 – 2(6)(3√2)
= 54 – 36√2
5) 11 – 3√3 = (11 – 3√3)²
= 121 + 27 – 2(11)(3√3)
= 148 – 66√3
mark this as brainliast.