Question 4 of 5
What is the percentage increase in the area
of a rectangle if the sides are increased by
25%.

2 thoughts on “Question 4 of 5<br />What is the percentage increase in the area<br />of a rectangle if the sides are increased by<br />25%.<br />”

1. Answer:

   • The percentage increase in the area of a rectangle is 56.25 %.

   Step-by-step explanation:

   To Find:

   • What is the percentage increase in the area of a rectangle if the sides are increased by 25%.

   Let us assume:

   Dimension of a rectangle be,

   • Length = L
   • Breadth = B

   Area of rectangle = L × B

   • Area of rectangle = LB

   When the sides are increased by 25%.

   • Length = L + 25% of L = 1.25L
   • Breadth = B + 25% of B = 1.25B

   Area of new rectangle = 1.25L × 1.25B

   • Area of new rectangle = 1.5625LB

   Increase in area = 1.5625LB – LB

   • Increase in area = 0.5625LB

   Increase percent = (0.5625LB × 100)/LB %

   • Increase percent = 56.25LB/LB %
   • Increase percent = 56.25 %

   Hence,

   • The percentage increase in the area of a rectangle is 56.25 %.

   Reply

2. Solution :-

   When the length and breadth increased by 25%

   New length = Length + 25% of Length

   New Length = l + 25/100 × l

   New Length = l + 25l/100

   New Length = 100l + 25l/100

   New Length = 125l/100

   For breadth

   New Breadth = Breadth + 25% of Breadth

   New Breadth = b + 25/100 × b

   New Breadth = b + 25l/100

   New= 100b + 25b/100

   New Breadth = 125b/100

   For Area

   Area = 125l/100 × 125b/100

   Area = 1.25l × 1.25b

   Area = 1.5625 lb²

   The increase in area = New Area – Original Area

   Increase = 1.5625lb – lb

   Increase in % = 0.5625lb × 100/lb

   Increase in % = 56.25lb/lb

   Increase in % = 56.25

   Increase = 0.5625 lb

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   Reply