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4. Evaluate using properties :
(i) 548 x 98
(ii) 924 x 988
(ii) 3023 x 723
5. Evaluate using properties :
By Charlie

4. Evaluate using properties :
(i) 548 x 98
(ii) 924 x 988
(ii) 3023 x 723
5. Evaluate using properties :
(i) 679 x 8 + 679 x 2
(ii) 284 x 12 – 284 x 2
(iii) 55873 x 94 + 55873 x 6
(iv) 7984 x 15 – 7984 x 5
(v) 8324 x 1945 – 8324 x 945
(vi) 3333 x 987 + 13 x 3333
roduct of the

please help as fast as u can​

About the author
Charlie

A conical heap of wheat of diameter 3.5 m is 12 m high. How much wheat is contained
by the heap.​

The perimeter and area of a square will always have the same numerical
value.
a. Not possible
b. True if each side

1 thought on “4. Evaluate using properties :<br />(i) 548 x 98<br />(ii) 924 x 988<br />(ii) 3023 x 723<br />5. Evaluate using properties :<br /”

  1. Step-by-step explanation:

    (i) 548 x 98 = (500 + 40 + 8) x 98 = 500 x 98 + 40 x 98 + 8 x 98 = 49000 + 3920 + 784 = 53704

    (ii) 924 x 988 = (900 + 20 + 4) x 988 = 900 x 988 + 20 x 988 + 4 x 988 = 889200 + 19760 + 3952 = 912912

    (iii) 3023 x 723 = (3000 + 20 + 3) x 723 = 3000 x 723 + 20 x 723 + 3 x 723 = 2169000 + 14460 + 2169 = 2185629

    5. (i) 679 x 8 + 679 x 2

    = 679 x (8 + 2) (using distributivity)

    = 679 x 10 = 6790

    (ii) 284 x 12 – 284 x 2

    = 284 x (12 – 2) (using distributivity)

    = 284 x 10 = 2840

    (iii) 55873 x 94 + 55873 x 6

    = 55873 x (94 + 6) (using distributivity)

    = 55873 x 100 = 55873

    (iv) 7984 x 15 – 7984 x 5

    = 7984 x (15 – 5) (using distributivity)

    = 7984 x 10 = 79840

    (v) 8324 x 1.945 – 8324 x 945

    = 8324 x (1945 – 945) (using distributivity)

    = 8324 x 1000 = 8324000

    (vi) 3333 x 987 + 13 x 3333

    = 3333 x (987 + 13) (using distributivity)

    = 3333 x 1000 = 3333000

    (please mark me as brainly list)

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