(1)Checkwhetherp(x)is a multiple of g(x)o rnot.

p(x)=x3-5×2+4x-3; g(x)=x–2​

2 thoughts on “(1)Checkwhetherp(x)is a multiple of g(x)o rnot.<br /><br />p(x)=x3-5×2+4x-3; g(x)=x–2​”

1. x

   3

   −5x

   2

   +4x−3,

   g(x)=x−2

   =>x−2=0

   =>x=2

   Now, p(2) should be 0 if p(x) is a multiple of g(x)

   Thus,

   p(2)=2

   3

   −5(2)

   2

   +4(2)−3

   =8−20+8−3

   =−7

   =8−20+8−3

   

   =0

   Reply

2. Answer:

   no

   Step-by-step explanation:

   p(x) is not a multiple of g(x)

   from g(x) , x=2

   when we put x=2 in p(x)

   p(x) is not equal to zero

   so p(x) is not a multiple of g (x)

   Reply