A book contains 250 pages. A boy read 20, 18 and 12 pages respectively in three consecutive days. What part of the book did he rea

2 thoughts on “A book contains 250 pages. A boy read 20, 18 and 12 pages respectively in three consecutive days. What part of the book did he rea”

1. Step-by-step explanation:

   Given:–

   A book contains 250 pages. A boy read 20, 18 and 12 pages respectively in three consecutive days.

   To find:–

   What part of the book did he read in 3 days and what part of the whole book has yet to be read by him?

   Solution:–

   Total number of pages in a book = 250

   Reading pages in the first day by a boy = 20

   Reading pages in the second day by the boy=18

   Reading pages in the third day by the boy = 12

   Total reading pages in the book in all three consecutive days

   =20+18+12

   =50

   Total number of pages has been read by the boy = 50

   The part of the reading pages in the total pages

   =Reading pages / Total pages

   = 50/250

   =1/5

   The boy read 1/5th part of the book .

   Remaining pages = Total pages – Already read pages

   => 250-50

   = 200

   The part of the remaining pages

   = Remaining pages / Total pages

   = 200/250

   = 20/25

   =4/5

   Answer:–

   The boy read 1/5th of the book.

   The boy has yet to be read 4/5th of the book.

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2. Answer:

   1st part solution.

   • 20 +18+12 = 50
   • Therefore 50/250 =1/5
   • so he has read 1/5 part of the book .

   2nd part solution.

   • Number of pages left (left means not read)
   • 250-50=200 (because he has read 50 pages)
   • Therefore 200/250= 4/5
   • so 4/5 part is still left ( left means not read)

   thankyou. (Hope it will help you)

   step by step explanation:

   Reply