*The length of a tangent drawn from a point at a distance of 10 cm of circle is 8 cm. The radius of the circle is …………* 1️⃣ 4 cm2️⃣ 5 cm3️⃣ 6 cm4️⃣ 7 cm About the author Athena
Given:- A circle with center O and AB is the tangent from point A. Radius of circle =OB=8cm Distance of point from the circle =AO=10cm To find:- Length of tangent, i.e., AB=? Solution:- Since AB is tangent, Therefore, AB⊥OB[∵Tangent at any point of circle is perpendicular to the radius through point of contact] ⇒∠ABO=90° Hence △OAB is a right angle triangle. Using pythagoras theorem in △OAB, AO2=AB2+OB2 (10)2=AB2+(8)2 ⇒AB=100−64=6cm Hence the length of tangent is 6cm. Hence the correct answer is 6cm. Reply
[tex] \huge \fbox \orange{answer}[/tex] OP = 10cm; Radius OT = 8cm and OT is perpendicular to PT ln RT ie, Triangle OTP OP²= OT²+ PT² 10² = 8² +PT² PT² = 100-64 PT² = 36 PT = 6 therefore ur correct answer is option 3 [tex] \huge{6}[/tex] Reply
Given:- A circle with center O and AB is the tangent from point A.
Radius of circle =OB=8cm
Distance of point from the circle =AO=10cm
To find:- Length of tangent, i.e., AB=?
Solution:-
Since AB is tangent,
Therefore,
AB⊥OB[∵Tangent at any point of circle is perpendicular to the radius through point of contact]
⇒∠ABO=90°
Hence △OAB is a right angle triangle.
Using pythagoras theorem in △OAB,
AO2=AB2+OB2
(10)2=AB2+(8)2
⇒AB=100−64=6cm
Hence the length of tangent is 6cm.
Hence the correct answer is 6cm.
[tex] \huge \fbox \orange{answer}[/tex]
OP = 10cm; Radius OT = 8cm
and OT is perpendicular to PT
ln RT ie, Triangle OTP
OP²= OT²+ PT²
10² = 8² +PT²
PT² = 100-64
PT² = 36
PT = 6
therefore ur correct answer is option 3
[tex] \huge{6}[/tex]