Point p(x,y) divides the line segment joining the points a(2,-5) and B (5,2) in the ratio 2:3 find the coordinates of p About the author Arianna
Answer: We can use the section formula: [tex]r = \frac{mr_{2} + nr_{1} }{m+n}[/tex] Given m:n = 2:3 So P(x) = (2 x 5 + 3 x 2)/(2+3) = 16/5 P(y) = (2 x 2 + 3 x -5)/(2+3) = -11/5 Coordinates of point P are : (16/5, -11/5) Do mark as brainliest if it helped! Reply
Answer:
We can use the section formula:
[tex]r = \frac{mr_{2} + nr_{1} }{m+n}[/tex]
Given m:n = 2:3
So P(x) = (2 x 5 + 3 x 2)/(2+3) = 16/5
P(y) = (2 x 2 + 3 x -5)/(2+3) = -11/5
Coordinates of point P are : (16/5, -11/5)
Do mark as brainliest if it helped!