sum of the digit of a two- digitnumber. is 9 when we interchange the digit, it is found that theresulting new number is greater thanthe original number by 27 whatthe two digit number? About the author Audrey
Answer: Let the digits at tens place and ones place: x and 9−x respectively. ∴ original number =10x+(9−x) = 9x+9 Now Interchange the digits: Digit at ones place and tens place: x and 9−x respectively. ∴ New number: 10(9−x)+x =90−10x+x =90−9x AS per the question New number = Original number +27 90−9x=9x+9+27 90−9x=9x+36 18x=54 x= 54÷18 x=3 Digit at tens place : 3 and one’s place : 6 ∴ Two digit number: 36 Hope it Helps, Slight Help taken from toppr, Byeeee Reply
Answer:
Let the digits at tens place and ones place: x and 9−x respectively.
∴ original number =10x+(9−x) = 9x+9
Now Interchange the digits: Digit at ones place and tens place: x and 9−x respectively.
∴ New number: 10(9−x)+x
=90−10x+x
=90−9x
AS per the question
New number = Original number +27
90−9x=9x+9+27
90−9x=9x+36
18x=54
x= 54÷18
x=3
Digit at tens place : 3 and one’s place : 6
∴ Two digit number: 36
Hope it Helps,
Slight Help taken from toppr,
Byeeee