divide the sum of 3/8 and – 5/12 by the reciprocal of – 15/8*16/27​

2 thoughts on “divide the sum of 3/8 and – 5/12 by the reciprocal of – 15/8*16/27​”

1. [tex]{\huge{\boxed{\sf{\green{Question}}}}}[/tex]

   Divide the sum of 3/8 and – 5/12 by the reciprocal of – 15/8*16/27​

   [tex]{\huge{\underline{\bf{\pink{➵ANSWER :-​✵}}}}}[/tex]

   The value of the sum of 3/8 and (-5/12) by the reciprocal of (-15/8 × 16/27) is 5/108..

   Solution:

   Sum of

   [tex]\begin{gathered}\begin{array} { c } { \frac { 3 } { 8 } \text { and } – \frac { 5 } { 12 } = \frac { 3 } { 8 } + \left( – \frac { 5 } { 12 } \right) = \frac { 3 } { 8 } – \frac { 5 } { 12 } = \frac { 9 – 10 } { 24 } = – \frac { 1 } { 24 } } \\\\ { – \frac { 15 } { 8 } \times \frac { 16 } { 27 } = – \frac { 10 } { 9 } } \end{array}\end{gathered} 83​ and − 125​ = 83​ +(− 125​ )= 83​ − 125​ = 249−10​ =− 241​ − 815​ × 2716​ =− 910[/tex]

   And, reciprocal of [tex]-\frac{10}{9} =-\frac{9}{10}− 910​ =− 109[/tex]

   Hence, on dividing-[tex]-\frac{1}{24} and -\frac{9}{10}− 241​[/tex] and−

   10

   9

   [tex]= – \frac { 1 } { 24 } \div – \frac { 9 } { 10 } = \frac { 1 } { 24 } \times \frac { 10 } { 9 } = \frac { 5 } { 108 }=− 241​ ÷− 109​ = 241​ × 910​ = 1085[/tex]

   Hence the answer is 1085!

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2. Step-by-step explanation:

   {3/8 + ( -5/12)} ÷( reciprocal of -15/8 x 16/27)

   {(9 – 10)/24 }÷( reciprocal of -10/9)

   -1/24 ÷ -9/10

   -1/24 × -10/9

   5/108

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