Answer: The value of x is ±4/9 Step-by-step explanation: Here [tex]4/3, x , 4/27[/tex] are in G.P. series Now, [tex]x^{2} = (4/3)*(4/27)[/tex] ⇒[tex]x^{2} =16/81[/tex] ⇒x = ±4/9 Reply
Answer:
The value of x is ±4/9
Step-by-step explanation:
Here [tex]4/3, x , 4/27[/tex] are in G.P. series
Now,
[tex]x^{2} = (4/3)*(4/27)[/tex]
⇒[tex]x^{2} =16/81[/tex]
⇒x = ±4/9