If [tex] \frac{ {2}^{x}}{ {2}^{x} + 1} = 3[/tex], then find the value of [tex] \frac{ {8}^{x}}{ {8}^{x} + 1} [/tex] About the author Aaliyah
Step-by-step explanation: multiply both side by 4 then{8}^{x}}{ {8}^{x} + 4} will be formed and could be written as {8}^{x}}{ {8}^{x} + 3+1} therefore{ {8}^{x}}{ {8}^{x} + 1} will be 12-3 =9 Reply
Step-by-step explanation:
multiply both side by 4
then{8}^{x}}{ {8}^{x} + 4} will be formed
and could be written as {8}^{x}}{ {8}^{x} + 3+1}
therefore{ {8}^{x}}{ {8}^{x} + 1} will be 12-3
=9