please answer by solvingthree numbers are in continued proportion the product of extremes is 196 and their sum is 35 find the middle number one of the extremes is 7 About the author Daisy
Answer: let the there numbers be a,b,c As they are in continued Proportion b 2 =ac mean is 12 ∴b=12 So, 12 2 =ac 144=ac c=144/a Sum of two number is a+c=26 a+ a 144 =26 Solving, =a 2 +144−26a=0 =a 2 −18a−8a+144=0 =a(a−18)−8(a−18)=0 =(a−18)(a−8)=0 ∴a=18 or a=8 c=8 c=18 ∴ The numbers are :- 8,12,18 or 18,12,8 Reply
Answer:
let the there numbers be
a,b,c
As they are in continued
Proportion
b
2
=ac
mean is 12
∴b=12
So, 12
2
=ac
144=ac
c=144/a
Sum of two number is
a+c=26
a+
a
144
=26
Solving,
=a
2
+144−26a=0
=a
2
−18a−8a+144=0
=a(a−18)−8(a−18)=0
=(a−18)(a−8)=0
∴a=18 or a=8
c=8 c=18
∴ The numbers are :-
8,12,18 or 18,12,8