please answer by solving3 number are in continued proportion the sum of second and third is 16 and the product of all is 8000 find the sum of all three numbers About the author Adalyn
Answer: let the there numbers be a,b,c As they are in continued Proportion b 2 =ac mean is 12 ∴b=12 So, 12 2 =ac 144=ac c=144/a Sum of two number is a+c=26 a+ a 144 =26 Solving, =a 2 +144−26a=0 =a 2 −18a−8a+144=0 =a(a−18)−8(a−18)=0 =(a−18)(a−8)=0 ∴a=18 or a=8 c=8 c=18 ∴ The numbers are :- 8,12,18 or 18,12,8 Reply
Answer:
let the there numbers be
a,b,c
As they are in continued
Proportion
b
2
=ac
mean is 12
∴b=12
So, 12
2
=ac
144=ac
c=144/a
Sum of two number is
a+c=26
a+
a
144
=26
Solving,
=a
2
+144−26a=0
=a
2
−18a−8a+144=0
=a(a−18)−8(a−18)=0
=(a−18)(a−8)=0
∴a=18 or a=8
c=8 c=18
∴ The numbers are :-
8,12,18 or 18,12,8