there are six red marbles 4 green and 2 white marbles in a box what is the probability of drawing a non white marble ?

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there are six red marbles 4 green and 2 white marbles in a box what is the probability of drawing a non white marble ?

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2 thoughts on “there are six red marbles 4 green and 2 white marbles in a box what is the probability of drawing a non white marble ?<br /><br />”

  1. [tex]\large\green{\bold{Given:}}[/tex]

    There are six red marbles 4 green and 2 white marbles in a box.

    [tex]\large\green{\bold{To \: find}}[/tex]

    What is the probability of the drawing a non white marble?

    [tex]\large\green{\bold{Solution}}[/tex]

    Total numbers of marbles = Red marbles + Green marbles + White marbles = 6 + 4 + 2 = 12

    • [tex]\large\green{\bold{As \: we \: know \: that, }}[/tex]

    ★[tex]\large \: probabiliy = \frac{favourable \: outcome }{total \: number \: of \: outcome} [/tex]

    Consider probability of getting non white be P(E)

    • Non white marble = Green marble + red marble = 6 + 4 = 0

    [tex] \implies[/tex]P(E) = [tex]\large \frac{10}{12} [/tex] = [tex]\large \frac{5}{6} [/tex]

    .·. The probability of getting non white marble is [tex]\large \frac{5}{6} [/tex]

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  2. Step-by-step explanation:

    P(Both Red) + P(Second is Red):

    P(Both Red) =(22)(92)

    P(Second is Red) =(71)(21)(92)

    This comes out to be 512.

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