If two angles of a triangle are 29 and 105 then find the third angle indegree. About the author Sadie
answer : third angle will b 45 Step-by-step explanation: solution ——> Given let asume Δ ABC now we have; \begin{gathered} < a = 30 \\ \\ < b = 105 \\ \\ < c = \end{gathered} <a=30 <b=105 <c= As we all know sum of all angle of triangle =180 so as per condition we write <a + < b + < c = 180 \begin{gathered}30 + 105 + < c = 180 \\ \\ 135 + < c \: = 180 \\ \\ < c = 180 – 135 \\ \\ < c = 45\end{gathered} 30+105+<c=180 135+<c=180 <c=180−135 <c=45 so third angle will b 45 Reply
We know that the sum of the interior angles of a triangle is 180∘. Let third angle in all the given triangles be x∘. Therefore, (i) 38∘+100∘+x∘=180∘ x∘=180∘−138∘ x∘=42∘ Reply
answer :
third angle will b 45
Step-by-step explanation:
solution ——>
Given
let asume Δ ABC
now
we have;
\begin{gathered} < a = 30 \\ \\ < b = 105 \\ \\ < c = \end{gathered}
<a=30
<b=105
<c=
As we all know sum of all angle of triangle =180
so as per condition we write
<a + < b + < c = 180
\begin{gathered}30 + 105 + < c = 180 \\ \\ 135 + < c \: = 180 \\ \\ < c = 180 – 135 \\ \\ < c = 45\end{gathered}
30+105+<c=180
135+<c=180
<c=180−135
<c=45
so third angle will b 45
We know that the sum of the interior angles of a triangle is 180∘. Let third angle in all the given triangles be x∘. Therefore,
(i) 38∘+100∘+x∘=180∘
x∘=180∘−138∘
x∘=42∘