A geometric sequence its 4th term un = 135 and the ratioU.= 3$ .If S10 = p(q-1) thenU4find the constants p and q.10 About the author Amaya
[tex]\huge\purple{\mathbb{Hello}}[/tex]Given : a geometric sequence 4th term u4= 135 and the ratio u9/u4=3^5 s10=p(q-1 To find : the constants p and q Solution: a = first term , r = common ratio 4th term u4 = ar³ 9th term u9 = ar⁸ u9/u4=3⁵ => ar⁸ / ar³ = 3⁵ => r⁵ = 3⁵ => r = 3 ar³ = 135 => a (3)³ = 135 => a = 5 a = 5 , r = 3 , n = 10 Sₙ = a(rⁿ – 1)/(r – 1) = 5 ( 3¹⁰ – 1) / ( 3 – 1) = 5 ( 3¹⁰ – 1) /2 = (5/2) ( 3¹⁰ – 1) p = 5/2 and q = 3¹⁰ One option other (5/2) ( 3¹⁰ – 1) = (5/2) ( 3⁵ + 1) (3⁵ – 1) = (5/2) ( 243 + 1) (243 – 1) = 610 (243 – 1) p = 610 and q = 243 Learn More: find the GP for which the sum of the first two terms is -4 and the fifth … brainly.in/question/7696369 Reply
Given : a geometric sequence 4th term u4= 135 and the ratio u9/u4=3^5 s10=p(q-1 To find : the constants p and q Solution: a = first term , r = common ratio 4th term u4 = ar³ 9th term u9 = ar⁸ u9/u4=3⁵ => ar⁸ / ar³ = 3⁵ => r⁵ = 3⁵ => r = 3 ar³ = 135 => a (3)³ = 135 => a = 5 a = 5 , r = 3 , n = 10 Sₙ = a(rⁿ – 1)/(r – 1) = 5 ( 3¹⁰ – 1) / ( 3 – 1) = 5 ( 3¹⁰ – 1) /2 = (5/2) ( 3¹⁰ – 1) p = 5/2 and q = 3¹⁰ One option other (5/2) ( 3¹⁰ – 1) = (5/2) ( 3⁵ + 1) (3⁵ – 1) = (5/2) ( 243 + 1) (243 – 1) = 610 (243 – 1) p = 610 and q = 243 Learn More: find the GP for which the sum of the first two terms is -4 and the fifth … brainly.in/question/7696369 A geometric sequence its 4th term https://brainly.in/question/40217224 Reply
[tex]\huge\purple{\mathbb{Hello}}[/tex]Given : a geometric sequence
4th term u4= 135 and
the ratio u9/u4=3^5
s10=p(q-1
To find : the constants p and q
Solution:
a = first term , r = common ratio
4th term u4 = ar³
9th term u9 = ar⁸
u9/u4=3⁵
=> ar⁸ / ar³ = 3⁵
=> r⁵ = 3⁵
=> r = 3
ar³ = 135
=> a (3)³ = 135
=> a = 5
a = 5 , r = 3 , n = 10
Sₙ = a(rⁿ – 1)/(r – 1)
= 5 ( 3¹⁰ – 1) / ( 3 – 1)
= 5 ( 3¹⁰ – 1) /2
= (5/2) ( 3¹⁰ – 1)
p = 5/2 and q = 3¹⁰
One option
other
(5/2) ( 3¹⁰ – 1)
= (5/2) ( 3⁵ + 1) (3⁵ – 1)
= (5/2) ( 243 + 1) (243 – 1)
= 610 (243 – 1)
p = 610 and q = 243
Learn More:
find the GP for which the sum of the first two terms is -4 and the fifth …
brainly.in/question/7696369
Given : a geometric sequence
4th term u4= 135 and
the ratio u9/u4=3^5
s10=p(q-1
To find : the constants p and q
Solution:
a = first term , r = common ratio
4th term u4 = ar³
9th term u9 = ar⁸
u9/u4=3⁵
=> ar⁸ / ar³ = 3⁵
=> r⁵ = 3⁵
=> r = 3
ar³ = 135
=> a (3)³ = 135
=> a = 5
a = 5 , r = 3 , n = 10
Sₙ = a(rⁿ – 1)/(r – 1)
= 5 ( 3¹⁰ – 1) / ( 3 – 1)
= 5 ( 3¹⁰ – 1) /2
= (5/2) ( 3¹⁰ – 1)
p = 5/2 and q = 3¹⁰
One option
other
(5/2) ( 3¹⁰ – 1)
= (5/2) ( 3⁵ + 1) (3⁵ – 1)
= (5/2) ( 243 + 1) (243 – 1)
= 610 (243 – 1)
p = 610 and q = 243
Learn More:
find the GP for which the sum of the first two terms is -4 and the fifth …
brainly.in/question/7696369
A geometric sequence its 4th term
https://brainly.in/question/40217224