Answer: It is not a collinear. Step-by-step explanation: (1, 5), (2, 3), (-2, -1) (x1, y1) (x2, y2) (x3, y3) 1/2[x1(y2-y3)+x2(y3-y1)+x3(y2-y1)] =1/2[1(3-(-1))+2(-1-5)+(-2)(3-5)] =1/2[1(3+1)+2(-6)-2(-2)] =1/2[1(4)-12+4] =1/2[4-8] =1/2[-4] =-4/2 =-2. Reply
Answer:
It is not a collinear.
Step-by-step explanation:
(1, 5), (2, 3), (-2, -1)
(x1, y1) (x2, y2) (x3, y3)
1/2[x1(y2-y3)+x2(y3-y1)+x3(y2-y1)]
=1/2[1(3-(-1))+2(-1-5)+(-2)(3-5)]
=1/2[1(3+1)+2(-6)-2(-2)]
=1/2[1(4)-12+4]
=1/2[4-8]
=1/2[-4]
=-4/2
=-2.