if q is the mean proportional between p and r prove that p²-q²+r²= q²[1/p²-1/q²+1/r²]​

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if q is the mean proportional between p and r prove that p²-q²+r²= q²[1/p²-1/q²+1/r²]​

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2 thoughts on “if q is the mean proportional between p and r prove that p²-q²+r²= q²[1/p²-1/q²+1/r²]​”

  1. Step-by-step explanation:

    −20

    −204

    −2042+7+6+x

    −2042+7+6+x

    −2042+7+6+x =15

    −2042+7+6+x =1515+x=60

    −2042+7+6+x =1515+x=60x=45

    −2042+7+6+x =1515+x=60x=45Now,

    −2042+7+6+x =1515+x=60x=45Now,5

    −2042+7+6+x =1515+x=60x=45Now,518+1+6+45+y

    −2042+7+6+x =1515+x=60x=45Now,518+1+6+45+y

    −2042+7+6+x =1515+x=60x=45Now,518+1+6+45+y =10

    −2042+7+6+x =1515+x=60x=45Now,518+1+6+45+y =1070+y=50

    −2042+7+6+x =1515+x=60x=45Now,518+1+6+45+y =1070+y=50y=−20

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  2. Answer:

    Answer. Since, q is the mean proportional of p and r. = p2 – pr + r2 = L.H.S. Hence proved

    Step-by-step explanation:

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