If
[tex]x + \frac{1}{x} = 5 \: \: \: then \: \: \: \: \: x {}^{3} + \frac{1}{x {}^{2} } [/tex]
[tex]x + \frac{1}{x} = 4 \: \: then \: {x}^{4} + \frac{1}{x {}^{4} } [/tex]
[tex]x + \frac{1}{x} = 3 \: \: then \: x {}^{6} + \frac{1}{x {}^{6} } [/tex]
[tex]x {}^{3} – \frac{1}{x {}^{3} } = 14 \: \: then \: x – \frac{1}{x} [/tex]
[tex]a + b + c = 9 \: \: and \: ab + bc + ca = 23 \: \: then \: {a}^{2} + b {}^{2} + c {}^{2} [/tex]
Answer:
X+1/X= 4 then x^4+1/x^4= 194
X+1/X= 3 then x^6+1/x^6= 322