please solve this question.. no irrelevant answer please…




the sum of three numbers, whose ratios ar

By Mia

please solve this question.. no irrelevant answer please…

the sum of three numbers, whose ratios are 3 \times \frac{1}{3} : 4 \times \frac{1}{5} : 6 \times \frac{1}{8} is 4917. find the numbers.

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2 thoughts on “please solve this question.. no irrelevant answer please…<br /><br /><br /><br /><br />the sum of three numbers, whose ratios ar”

  1. Answer:

    let the three numbers be x,y,z

    sum of the three numbers

    x+y+z = 4917

    their ratios x:y:z = 3⅓ : 4⅕ : 6⅛

    converting into improper fractions

    x:y:z = 10/3 : 21/5 : 49/8

    they all should have a common factor. let it be k

    x = 10/3 k

    y = 21/5 k

    z = 49/8 k

    substituting

    10/3 k + 21/5 k + 49/8 k = 4917

    400k + 504k + 735k / 120 = 4917

    1639k / 120 = 4917

    k = 3×120

    k = 360

    applying the values

    x = 10/3 × 360

    x = 1200

    y = 21/5 × 360

    y = 1512

    z = 49/8 × 360

    z = 2205

    so the numbers are 1200, 1512, 2205

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