– Prove that product of a two consecutive positive integersis divisible by 2. About the author Kennedy
Step by step explanation Let the 2 consecutive numbers be, x,x+1 product of these consecutive numbers, =x(x+1) (1) even let, x=2k product =2k[2k+1] from above equation it is clear that the product is divisible by 2 (2) odd let, x=2k+1 product =(2k+1)[(2k+1)+1] =2(2k2+3k+1) from above equation it is clear that the product is divisible by 2 Reply
Answer:
2×3 =6
it is divided by 2
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Step by step explanation
Let the 2 consecutive numbers be, x,x+1
product of these consecutive numbers, =x(x+1)
(1) even
let, x=2k
product =2k[2k+1]
from above equation it is clear that the product is divisible by 2
(2) odd
let, x=2k+1
product =(2k+1)[(2k+1)+1]
=2(2k2+3k+1)
from above equation it is clear that the product is divisible by 2