a ceartain sum of money invested for 5 years at 8 percent p.a simple intrest earns intrest of rupees12000 find 1 the sum of money 2 the compound intrest earned by this moey in two year at 10percent p.a compound intrest About the author Reagan
Answer: [tex]\huge\mathfrak\pink{Answer:}[/tex] Rate (R) = 8% p.a. Period (T) = 5 Years Interest (T) = ₹ 12000 (i) ∴ Sum = (I × 100)/(R × T) = ₹ ((12000 × 100)/(8 × 5)) = ₹ 30000 (ii) Rate (R) = 10% p.a. Time (T) = 2 Years Principal (P) = ₹30000 Interest for the first year = PRT/100 = ₹ ((30000 × 10 ×1)/100) = ₹3000 ∴ Amount after one year = ₹30000 + 3000 ₹ 33000 Principal for the second year = ₹ 33000 Interest for the second year = (33000 × 10 ×1)/100 = ₹ 3300 ∴ Compound interest for two years = ₹3000 + 3300 = ₹ 6300 I hope it would help uh out!❤️✌️ [tex]\huge\fbox\colorbox{pink}{Follow=Follow}[/tex] Reply
Answer: Rate (R) = 8% p.a. Period (T) = 5 Years Interest (T) = ₹ 12000 (i) ∴ Sum = (I × 100)/(R × T) = ₹ ((12000 × 100)/(8 × 5)) = ₹ 30000 (ii) Rate (R) = 10% p.a. Time (T) = 2 Years Principal (P) = ₹30000 Interest for the first year = PRT/100 = ₹ ((30000 × 10 ×1)/100) = ₹3000 ∴ Amount after one year = ₹30000 + 3000 ₹ 33000 Principal for the second year = ₹ 33000 Interest for the second year = (33000 × 10 ×1)/100 = ₹ 3300 ∴ Compound interest for two years = ₹3000 + 3300 = ₹ 6300 I hope it would help uh out!❤️✌️ Reply
Answer:
[tex]\huge\mathfrak\pink{Answer:}[/tex]
Rate (R) = 8% p.a.
Period (T) = 5 Years
Interest (T) = ₹ 12000
(i) ∴ Sum = (I × 100)/(R × T)
= ₹ ((12000 × 100)/(8 × 5)) = ₹ 30000
(ii) Rate (R) = 10% p.a.
Time (T) = 2 Years
Principal (P) = ₹30000
Interest for the first year = PRT/100
= ₹ ((30000 × 10 ×1)/100) = ₹3000
∴ Amount after one year = ₹30000 + 3000
₹ 33000
Principal for the second year = ₹ 33000
Interest for the second year = (33000 × 10 ×1)/100
= ₹ 3300
∴ Compound interest for two years
= ₹3000 + 3300 = ₹ 6300
I hope it would help uh out!❤️✌️
[tex]\huge\fbox\colorbox{pink}{Follow=Follow}[/tex]
Answer:
Rate (R) = 8% p.a.
Period (T) = 5 Years
Interest (T) = ₹ 12000
(i) ∴ Sum = (I × 100)/(R × T)
= ₹ ((12000 × 100)/(8 × 5)) = ₹ 30000
(ii) Rate (R) = 10% p.a.
Time (T) = 2 Years
Principal (P) = ₹30000
Interest for the first year = PRT/100
= ₹ ((30000 × 10 ×1)/100) = ₹3000
∴ Amount after one year = ₹30000 + 3000
₹ 33000
Principal for the second year = ₹ 33000
Interest for the second year = (33000 × 10 ×1)/100
= ₹ 3300
∴ Compound interest for two years
= ₹3000 + 3300 = ₹ 6300
I hope it would help uh out!❤️✌️