Prove that 1 b+c b2 + c2
1
c+a c2 + a2 = (b-c)(c- a)(a – b)
1 a + b a2 + b2​

1 thought on “Prove that 1 b+c b2 + c2<br />1<br />c+a c2 + a2 = (b-c)(c- a)(a – b)<br />1 a + b a2 + b2​”

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