Solve each of the following quadratic equations:
5. (2x – 3)(3x + 1) = 0
6. 4x² + 5x = 0​

2 thoughts on “Solve each of the following quadratic equations:<br />5. (2x – 3)(3x + 1) = 0<br />6. 4x² + 5x = 0​”

1. Step-by-step explanation:

   ohhhhhhhhkkkkkkkkkkkkkkk

   Reply

2. Answer:

   ⭐Question:-1

   (2x – 3)(3x + 1) = 0

   ☯️Answer:-

   1. [tex](2x – 3)(3x + 1) = 0 \\ [/tex]

   [tex] = > \: 2x – 3 = 0 \: or \: 3x + 1 = 0[/tex]

   [tex] = > \: 2x = 3 \: or \: 3x + 1= 0[/tex]

   [tex] = \geqslant x = \frac{3}{2 \: } \: or \: x = – \frac{1}{3} [/tex]

   [tex]hence \: the \: roots \: of \: the \: given \: question \: \\ are \: \frac{3}{2} \: and \: – \frac{1}{3} [/tex]

   ⭐Question:-2

   4x² + 5x = 0

   ☯️Answer:-

   2. [tex]we \: have \: 4x {}^{2} + 5x = 0[/tex]

   [tex] = > x \: (4x + 5) = 0[/tex]

   [tex] = > \: either \: x = 0 \: or \: 4x + 5 = 0[/tex]

   [tex] = > x = 0 \: or \: 4x + 5 = 0[/tex]

   [tex] = > x = 0 \: or \: x = \frac{ – 5}{4} [/tex]

   [tex]thus,\: [/tex]

   [tex]x = 0 \: and \: x = \frac{ – 5}{4} \: are \: two \: roots \: of \\ equation \: 4x {}^{2} + 5x = 0[/tex]

   Reply