the equation for a hyperbola is shown x^2/25 – y^2/49=1 what are the lengths of the transverse and conjugate axes? About the author Adalynn
Answer: The equation 16x^2 – 9y^2 = 144. can be written as x^2/9 – y^2/16 = – 1 This is of the form x^2/a^2 – y^2/b^2 – 1 a^2 = 9,b^2 = 16 a = 3,b = 4 Length Reply
Answer:
The equation 16x^2 – 9y^2 = 144. can be written as x^2/9 – y^2/16 = – 1 This is of the form x^2/a^2 – y^2/b^2 – 1 a^2 = 9,b^2 = 16 a = 3,b = 4 Length