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Suraj spent 28,500rupees in mowing his lawn which is in the shape of a trapezium.
The rate of mowing is rupees 38 per sq. m.

By Brielle

Suraj spent 28,500rupees in mowing his lawn which is in the shape of a trapezium.
The rate of mowing is rupees 38 per sq. m. The parallel sides are 24 m and
36 m. What is the distance between the parallel sides?
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Brielle

1/3 X (2/3 + 4/5)=(1/3 X 2/3)+ ( ——-X ________ )
1.)2/3 ,4/5
2.)4/5, 2/3
3.)1/3 ,2/3
4.)1/3 ,4/5
Plea

(5) Conscept of the divisibility only exists in sets of
(A)- natural numbers
(B) integers
(D) real numbers
(C

1 thought on “Suraj spent 28,500rupees in mowing his lawn which is in the shape of a trapezium.<br />The rate of mowing is rupees 38 per sq. m.”

  1. Rs. 38 are spent for mowing = 1 sq.m.
    Re. 1 is spent for mowing = 1/38 sq.m.
    Rs. 28,500 are spent for mowing
    = 28,500/ 38
    = 750 sq.m.
    So, area of trapezium is 750 sq.m.
    As we know,
    Area of trapezium = 1/2 (sum of parallel sides) ( height)
    750 = 1/2 (24+36) (height)
    750 = 60/2 (height)
    750 = 30 (height)
    => Height = 750/30 = 25m
    Therefore, distance between the parallel sides or height is equal to 25 m

    Reply

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