what is the remainder when f(x)= x^2-3(x+3 divided by g(x)= x-1

what is the remainder when f(x)= x^2-3(x+3 divided by g(x)= x-1

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2 thoughts on “what is the remainder when f(x)= x^2-3(x+3 divided by g(x)= x-1”

  1. Answer:

    -13

    Step-by-step explanation:

    f(x) = x²-3(x+3) = x²-3x-9

    g(x) = x-1, also g(x) = 0

    => x-1 = 0

    => x = 1

    Substituting 1 at place of x,

    (1)² – 3(1) – 9 = 1 – 3 – 9 = -13

    Hence, the remainder is -13.

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