In the given figure, ABCD is a cyclic quadrilateral inscribed in a circle with centre O. CD is produced to E such that ADE = 75°. If ABO = 40°, then OAC = About the author Eden
Answer: ABCD is a cyclic quadrilateral with center O. Therefore OA=OA=OC are the radii of circle In △AOB, OA=OB, therefore ∠ABO=∠BAO=∠BAC=45∘ [Angles opposite to equal sides] ∠OCA− cannot be determined. Because AOC is a line, ∠AOC=180∘  Step-by-step explanation: please mark me brainliest please.. Reply
Answer:
ABCD is a cyclic quadrilateral with center O.
Therefore OA=OA=OC are the radii of circle
In △AOB, OA=OB, therefore
∠ABO=∠BAO=∠BAC=45∘ [Angles opposite to equal sides]
∠OCA− cannot be determined. Because
AOC is a line, ∠AOC=180∘

Step-by-step explanation:
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