Find the value of x if x,(2x+13°),(3x+10°) and (x-6°) are the angles of a quadrilateral?

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Answer:   angles of quadrilateral =x,(2x+13),(3x+10),(x-6)  sum of angles of a quadrilateral=360degree   x+(2x+13)+(3x+10)+(x-6)=360  x+2x+13+3x+10+x-6=360  7x+17=360  7x=360-17= 343  7x=343  x =343/7=49  therefore value of x is 49  pls mark as brainliest   Step-by-step explanation:

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