A body starts from rest and travels with a unifom acceleration a to make a displacement is 6m/s then its unifom acceleration is​

2 thoughts on “A body starts from rest and travels with a unifom acceleration a to make a displacement is 6m/s then its unifom acceleration is​”

1. Appropriate Question:-

   A body starts from rest and travels with a unifom acceleration a to make a displacement is 6m with velocity of 6m/s. Then its unifom acceleration??

   Given:–

   • A body starts from rest and travels with a unifom acceleration a to make a displacement is 6m/s.

   To Find:–

   • It’s unifom acceleration

   Equation used:–

   • [tex]{\boxed{\bf{v^2=2as+u^2}}}[/tex]

   Here,

   • v = Final Velocity

   • u = Initial Velocity

   • a = Acceleration

   • S = Displacement

   Solution:–

   Using, v² = 2as + u²

   Here,

   • v = 6m/s

   • S = 6m

   • u = 0m/s

   Putting Values,

   [tex]\sf \implies\:6^2=2\times a \times 6+0^2[/tex]

   [tex]\sf \implies\:12a=36[/tex]

   [tex]\sf \implies\:a=\dfrac{36}{12}[/tex]

   [tex]\sf \implies\:a=\dfrac{9}{3}[/tex]

   [tex]\bf \implies\:a=3ms^{-2}[/tex]

   Hence, It’s Unifom Acceleration is 3m/s².

   ━━━━━━━━━━━━━━━━━━

   More Equations of Motion:-

   • [tex]\bf v=u+at[/tex]

   • [tex]\bf S=ut+\dfrac{1}{2}at^2[/tex]

   ━━━━━━━━━━━━━━━━━━

   Reply

2. Correct Question !!

   A body starts from rest and travels with a unifom acceleration a to make a displacement of 6m and its final velocity is 6m/s then its unifom acceleration is ?

   Given:–

   • Initial velocity ,u = 0m/s
   • Final velocity ,v = 6m/s
   • Displacement,s = 6m

   To Find:–

   • Acceleration ,a

   Solution:–

   ⠀⠀⠀⠀⠀⠀⠀⠀According to the Question

   It is given that the body starts from rest & cover a displacement of 6 m with velocity 6m/s. We calculate the acceleration of the body . Using 3rd equation of motion

   • v² = u² + 2as

   where,

   • v denote final velocity
   • u denote initial velocity
   • a denote acceleration
   • s denote displacement

   Substitute the value we get

   [tex]:\implies[/tex] 6² = 0² + 2×a × 6

   [tex]:\implies[/tex] 36 = 0 + 12a

   [tex]:\implies[/tex] 36 = 12a

   [tex]:\implies[/tex] 12a = 36

   [tex]:\implies[/tex] a = 36/12

   [tex]:\implies[/tex] a = 3m/s²

   • Hence, the uniform acceleration of the body is 3m/s².

   Reply