Solution of the D.E y” – 4y + 4y = ex when solved
undetermined coefficients is
a) y = (C+ + C2) e2x + 2e – 1
b) y =

Solution of the D.E y” – 4y + 4y = ex when solved
undetermined coefficients is
a) y = (C+ + C2) e2x + 2e – 1
b) y = (C+ C2 x) e2x + 4e* – 4
c) y = (C+ + C2 x) e2x + ex
d) y = (C1 + C2 x) ex + 4ex
Solution of the D.E y” + 3y’ + 2y = 12×2 when solv
method of undetermined coefficients is
a) y = C1 et + C2 e2x + 2 – 11x + x2
b) y = C1 e-* + C2 e-2x + 18+ 21x + 3×2
c) y = C1 ex + C2 e – 2x + 11 + 18x + 2×2
l) y = C1 e – + C2 e – 2x + 21 – 18x + 6×2​