Step-by-step explanation: let 1st integer = x then 2nd integer = x+1 then 3rd integer = x+2 A.T.Q x + x+1 + x+2 = 45 3x + 3 = 45 3x = 45-3 3x = 42 x = 42/3 x = 14 1st integer = x = 14 2nd integer = x+1 = 14 +1 = 15 3rd integer = x+2 = 14+2 = 16 Reply
Answer: The the consecutive integers are 14,15, and 16 Step-by-step explanation: Let the no.s be x,x+1 and x+2 Therefore,according to the given condition, x+x+1+x+2=45 3x+3=45 3x=42 x=14 Therefore, First integer = x =14 Second Integer = x+1 =15 Third Integer = x+2 = 16 The the consecutive integers are 14,15, and 16 Hope it helps Reply
Step-by-step explanation:
let 1st integer = x
then 2nd integer = x+1
then 3rd integer = x+2
A.T.Q
x + x+1 + x+2 = 45
3x + 3 = 45
3x = 45-3
3x = 42
x = 42/3
x = 14
1st integer = x
= 14
2nd integer = x+1 = 14 +1
= 15
3rd integer = x+2 = 14+2
= 16
Answer:
The the consecutive integers are 14,15, and 16
Step-by-step explanation:
Let the no.s be x,x+1 and x+2
Therefore,according to the given condition,
x+x+1+x+2=45
3x+3=45
3x=42
x=14
Therefore,
First integer = x =14
Second Integer = x+1 =15
Third Integer = x+2 = 16
The the consecutive integers are 14,15, and 16
Hope it helps