9. The dimensions of a cuboidal box are in the ratio 3:2:1 and the total surface area is
2,816 sq cm. Find its weight if dens

9. The dimensions of a cuboidal box are in the ratio 3:2:1 and the total surface area is
2,816 sq cm. Find its weight if density of the cuboidal box is 1 g/cm​

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1 thought on “9. The dimensions of a cuboidal box are in the ratio 3:2:1 and the total surface area is<br />2,816 sq cm. Find its weight if dens”

  1. Step-by-step explanation:

    I think the weight should be 1g/cm³

    Here, let

    l= 3x

    b= 2x and h= x

    TSA= 2(lb+lh+bh)

    2816cm²= 2(6x²+3x²+2x²)

    2816cm²=2×11x²

    256cm²=2x²

    x= √256/2= 16/√2 = (8√2)cm

    Vol³= l×b×h

    = 3(8√2)cm ×2(8√2)cm×(8√2)cm

    = 6cm³×512√8

    =3072cm3×2√2= (6144√2)cm3= 8663.04cm3

    therefore its weight= 8663.04cm³×1g/cm³= 8863.04g

    or 8.86304 kg

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