8. The numerator of a fraction is smaller than its denominator by 1. If the numerator is
increased by 4 and the denominator i

2 thoughts on “8. The numerator of a fraction is smaller than its denominator by 1. If the numerator is<br />increased by 4 and the denominator i”

1. Answer:

   Required Answer :-

   Let the fraction be x – 1/x

   [tex] \sf \dfrac{x – 1 + 4}{2x} = 1[/tex]

   [tex] \sf \: \dfrac{x + 3}{2x} = 1[/tex]

   [tex] \sf \: x + 3 = 2x[/tex]

   [tex] \sf \: 2x – x = 3[/tex]

   [tex] \sf \: x = 3[/tex]

   Fraction = 3 – 1 + 4/2(3)

   Fraction = 2/3

   V E R I F I C A T I O N :

   [tex] \sf \: \dfrac{3 – 1 + 4}{2(3)} = 1[/tex]

   [tex] \sf \: \dfrac{7 – 1}{6} = 1[/tex]

   [tex] \sf \: \dfrac{6 }{6} = 1[/tex]

   [tex] \sf \: 1 = 1[/tex]

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2. Question:–

   • The numerator of a fraction is smaller than its denominator by 1. If the numerator is increased by 4 and the denominator is doubled the number becomes 1. Find the fraction.

   To Find:–

   • Find the fraction.

   Solution:–

   Here ,

   • Let numerator be x – 1

   • Denominator be x

   According to the Question:-

   [tex]\tt\implies \: \dfrac { x – 1 + 4 } { 2x } = 1 [/tex]

   [tex]\tt\implies \: x + 3 = 2x [/tex]

   [tex]\tt\implies \: 2x – x = 3 [/tex]

   [tex]\tt\implies \: x = 3 [/tex]

   Hence ,

   • Denominator is 3

   • Numerator is x – 1 = 2

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