8. The capacitance of a parallel plate capacitors
60 MF. If the distance betweon the plates is
tripled and the area doub

1 thought on “8. The capacitance of a parallel plate capacitors<br />60 MF. If the distance betweon the plates is<br />tripled and the area doub”

1. Answer:

   Let the distance between the plates initially be d.

   Thus initial capacitance C

   1

   =ϵ

   o

   A/d=8 pF

   Substance of dielectric constant K=6 is inserted between the plates.

   Also, now the distance between the plates is d

   ′

   =0.5d

   Thus new capacitance C

   2

   =Kϵ

   o

   A/d

   ′

   ∴ C

   2

   =6ϵ

   o

   A/0.5d=12C

   1

   =96 pF

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