8. In figure, AD = DB and ZB is a right angle. Determine
sin? 0 + cos2 0.
AN
64
Da
Ꮎ
C
B​

1 thought on “8. In figure, AD = DB and ZB is a right angle. Determine<br />sin? 0 + cos2 0.<br />AN<br />64<br />Da<br />Ꮎ<br />C<br />B​”

1. Answer:

   AB= a

   ⇒ AD + DB = a

   ⇒ AD + AD = a

   ⇒ 2 AD = a

   ⇒ AD = 2a

   Thus, AD = DB = 2a

   By Pythagoras theorem, we have

   AC2=AB2+BC2

   ⇒b2=a2+BC2

   ⇒BC2=b2−a2

   ⇒BC=b2−a2

   Thus, in ΔBCD, we have

   Base = BC = b2−a2 and Perpendicular = BD = 2a

   Applying Pythagoras theorem in Δ BCD, we have

   ⇒BC2+BD2=CD2

   ⇒(b2−a2)+(2a)2=CD2

   ⇒CD2=b<

   hope it was helpful

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