(7x-y-6)²+(14x+2y-16)²=0 solve by the method of elimination.​

1 thought on “(7x-y-6)²+(14x+2y-16)²=0 solve by the method of elimination.​”

1. Answer:

   
   (7x – y -6)^2=0
   

   
   7x – y – 6=0…eqn1
   

   
   2′nd term
   

   
   (14x + 2y -16)^2 =0
   

   
   7x + y -8 =0… eqn2
   

   
   solve eqn1 and eqn2
   

   
   we get x=1 & y=1…

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