7x² +44x+12=0
find the zeros of above and verify the relation between zeros and coefficients?​

1 thought on “7x² +44x+12=0 <br />find the zeros of above and verify the relation between zeros and coefficients?​”

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   7x² + 44x + 12 = 0

   7x² + 42x + 2x + 12 = 0

   7x ( x + 6 ) + 2 ( x + 6 ) = 0

   ( 7x + 2 ) ( x + 6 ) = 0

   7x + 2 = 0 , x + 6 = 0

   x = -2/7 , x = -6

   Hence , zeroes are -2/7 , -6

   let α = -2/7 , β = -6

   Sum of zeroes

   = α + β

   = -2/7 + ( -6 )

   = [-2 + ( -42 )] / 7

   = -44/7

   Product of zeroes

   = αβ

   = -2/7 × ( -6 )

   = -12/7

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