-(6a – b)(b +20)
Hence the factors of bab – B-2bc + 12ac are (64-byan
12ac = b (6a – b) +2c (6a – b)
By taking

-(6a – b)(b +20)
Hence the factors of bab – B-2bc + 12ac are (64-byan
12ac = b (6a – b) +2c (6a – b)
By taking
factoria
Exercise – 12.1
Find the common factors of the given terms in each
rto
the
(i) &r. 24
(ii) 3a, 21ab (i) Zry 35ry (w)4m?
(v) 15p, 20gr. 25rp (vi) 4x’, bry, dy’x (vii) 12 x’y, 1877
Factorise the following expressions
(1) 512_25
(m) 7pP+49
(ii) 90 — har​

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