6.
A powerful motorcycle can accelerate from rest to 32 m/s in only 4s.
(a) What is its average acceleration?
(6

2 thoughts on “6.<br /> A powerful motorcycle can accelerate from rest to 32 m/s in only 4s.<br /> (a) What is its average acceleration?<br /> (6”

1. Answer: Make use the following kinematics equations:

   SUVAT– s-displacement, u-initial velocity, v-final velocity,a- acceleration, t-timev=u + atv2 = u2 + 2ass=1/2(u+v)ts=ut + 1/2at2

   The values for the motor cycle are as follows:

   u= 0m/s

   v=28m/s

   t=4s

   a=??s=??

   v=u +at

   28= 0 + 4a

   4a=28 a= 7m/s2

   Therefore the average acceleration = 7m/s2

   displacement s, v2=u2+2as

   28^2= 0^2+(2x7s)

   784= 14s

   s= 784/14

   s= 56

   Therefore the distance travelled = 56 meters.

   MARK ME AS THE BRAINLIEST

   Reply

2. a power mortal word

   32 only

   Reply