5 years ago father’s age was 8 times of son’s age.Product of their present age is 450.Find their present age. About the author Ella
Answer: Let the age of father be x years and age of his son be ( 45 – x ) years, Five years ago, Age of father = ( x – 5 ) years Age of his son = ( 45 – x – 5 ) years = ( 40 – x ) years According to the question, Product of their ages five years ago = 4 × father’s age five years ago => ( x – 5 ) ( 40 – x ) = 4( x – 5 ) = > \cancel{(x – 5)}(40 – x) = 4 \cancel{(x – 5)}=> (x−5) (40−x)=4 (x−5) => 40 – x = 4 => 40 – 4 = x => 36 = x Hence, Present age of father = x years = 36 years Present age of his son = ( 45 – x ) = ( 45 – 36 ) = 9 years Reply
Answer:
Let the age of father be x years and age of his son be ( 45 – x ) years,
Five years ago,
Age of father = ( x – 5 ) years
Age of his son = ( 45 – x – 5 ) years = ( 40 – x ) years
According to the question,
Product of their ages five years ago = 4 × father’s age five years ago
=> ( x – 5 ) ( 40 – x ) = 4( x – 5 )
= > \cancel{(x – 5)}(40 – x) = 4 \cancel{(x – 5)}=>
(x−5)
(40−x)=4
(x−5)
=> 40 – x = 4
=> 40 – 4 = x
=> 36 = x
Hence,
Present age of father = x years = 36 years
Present age of his son = ( 45 – x ) = ( 45 – 36 ) = 9 years