5. The modelarectangle is ig 19cm² andits peremeter is 56 cm and thedimensions of the rectangle About the author Melanie
as area of rectangle is length × breadth given area = 19 cm ^2 and perimeter is 2×(l+b) l×b=19 then l=19/b 2×(l+b)=56 2(19/b+b)=56 36/b+2b/1=56 Reply
as area of rectangle is length × breadth
given area = 19 cm ^2
and perimeter is 2×(l+b)
l×b=19 then l=19/b
2×(l+b)=56
2(19/b+b)=56
36/b+2b/1=56