x²- 4ax- 4a²=5a⁴/x²- 4ax
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1. Answer:

   x=[-(-4a)+/-sqrt((-4a)^2–4*1*(4a^2-b^2))]/(2*1)

   = [(4a)+/-sqrt(16a^2–16a^2+4b^2))]/2

   =[4a+/-sqrt(4b^2))]/(2)=(4a+/-2b)/2

   Hence,

   x = (2a+b) or (2a-b).

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