40 is divided in two parts such that 1/5rd of first in
equal to the 1/3rd of the second
number. It first number is X.
By Cora

40 is divided in two parts such that 1/5rd of first in
equal to the 1/3rd of the second
number. It first number is X.
Then the equation for this is.​

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Cora

1 thought on “40 is divided in two parts such that 1/5rd of first in<br />equal to the 1/3rd of the second<br />number. It first number is X.<br”

  1. Answer:

    [tex] \frac{x}{5} + \frac{40 – x}{3} [/tex]

    Step-by-step explanation:

    First number = x

    Second number = 40 – x

    [tex] \frac{1}{5} x + \frac{1}{3} ( \frac{40 – x}{3} ) = \frac{x}{5} + \frac{40 – x}{3} [/tex]

    If we solve this equation we get the numbers as 25 and 15.

    [tex]\frac{x}{5} + \frac{40 – x}{3} \\ 3x + 5(40 – x) = 3x + 200 – 5x \: (by \: cross \: multiplication) \\ 3x + 5x = 200 \\ 8x = 200 \\ x = \frac{200}{8} = 25 \\ 40 – x = 40 – 25 = 15[/tex]

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