4Single Answer TypeReview LaterFour angles of a quadrilateral are in theratio 1: 2:3:4, The difference betweenthe greatest and the smallest angleisA125° About the author Eden
Answer: since angles are in ratio 1:2:3:4 therefore , x+2x+3x+4x=360 10x=360 x=36 therefore smallest angle is x so 36 and largest angle is 4x so 144 therefore difference between smallest and largest angle is 144-36 that is 108 Reply
Step-by-step explanation: let the angles be 1x ,2x,3x,4x now. x+ 2x+ 3x+ 4x = 360 10 x = 360° x= 360/10 x = 36° therefore The difference between the greatest and the smallest angle is (4x- x) = 144 – 36 = 108 ° THANK YOU PLEASE MARK IT AS BRAINLIEST Reply
Answer:
since angles are in ratio 1:2:3:4
therefore ,
x+2x+3x+4x=360
10x=360
x=36
therefore smallest angle is x so 36
and largest angle is 4x so 144
therefore difference between smallest and largest angle is 144-36
that is 108
Step-by-step explanation:
let the angles be 1x ,2x,3x,4x
now.
x+ 2x+ 3x+ 4x = 360
10 x = 360°
x= 360/10
x = 36°
therefore The difference between
the greatest and the smallest angle
is (4x- x) = 144 – 36 = 108 °
THANK YOU
PLEASE MARK IT AS BRAINLIEST