4. Find the least positive integer m such that
= (1+i/1-i) ^4m=1​

4. Find the least positive integer m such that
= (1+i/1-i) ^4m=1​

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  1. Answer:

    Given as [(1 + i)/(1 – i)]n Z = [(1 + i)/(1 – i)]n Now let us multiply and divide by (1 + i), we get = i [which is not real] For n = 2, we have [(1 + i)/(1 – i)]2 = i2 = -1 [which is real] Therefore, the smallest positive integral ‘n’ that can make [(1 + i)/(1 – i)]n real is 2. Thus, the smallest positive integral value of ‘n’ is 2.Read more on Sarthaks.com – https://www.sarthaks.com/660167/find-the-least-positive-integral-value-of-n-for-which-1-i-1-i-n-is-real

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