4. Find the co-ordinates of points on the x-axiswhich are at a distance of 17 units from thepoint (11, -8)the About the author Serenity
Let point be (x,0) Using distance formula: 17^2 = (x-11)^2 + (8)^2 289 = x^2+121-22x + 64 x^2-22x-104=0 x^2-26x+4x-104=0 x(x-26)+4(x-26)=0 (x+4)(x-26)=0 x= -4 and x=26 Therefore points are (-4,0) and (26,0) Please mark as brainliest answer Reply
Let point be (x,0)
Using distance formula:
17^2 = (x-11)^2 + (8)^2
289 = x^2+121-22x + 64
x^2-22x-104=0
x^2-26x+4x-104=0
x(x-26)+4(x-26)=0
(x+4)(x-26)=0
x= -4 and x=26
Therefore points are (-4,0) and (26,0)
Please mark as brainliest answer