4. Factorise :(i) x³-2x²-x+2(ii) x³-3x²-9x-5(iii) x³+13x²+23x+20(iv) 2y³+y²-2y-1 About the author Iris
Step-by-step explanation: Answer i) x³–2x²–x+2 = (x³–x)(2x²+2) =x(x²)+2(x²) =x²(x+2) ii) x³–3x²–9x-5 = (–3x²–9x)(x³–5) = –3x(3x-3)(x³–5) Reply
Step-by-step explanation:
Answer
i) x³–2x²–x+2
= (x³–x)(2x²+2)
=x(x²)+2(x²)
=x²(x+2)
ii) x³–3x²–9x-5
= (–3x²–9x)(x³–5)
= –3x(3x-3)(x³–5)